Question

y^2 +2(√3+1)y+2√3=0 помогите пжжжж

Answer 1

$dfrac D4=left(dfrac b2right)^2-ac=(sqrt3+1)^2-2sqrt3=3+2sqrt3+1-2sqrt3=4\ y_{1,2}=dfrac{-frac b2pmsqrt{frac D4}}a=dfrac{-(sqrt3+1)pm2}1\ y_1=-sqrt3-1-2=-sqrt3-3,quad y_2=-sqrt3-1+2=1-sqrt3$