Question

ДАЮ 20 БАЛЛОВ!
$27^{3-x} =9 5^{x} +3* 5^{x-2} =140 3^{ x^{2-x} } textless 9$

Answer 1

$27^3^-^x=9 \ 3^9^-^3^x=3^2 \ 9-3x=2 \ -3x=2-9 \ -3x=-7 \ x= frac{7}{3} \ \ \ 5^x+3*5^x^-^2=140 \ (5^2+3)*5^x^-^2=140 \ (25+3)*5^x^-^2=140 \ 28*5^x^-^2=140 \ 5^x^-^2=5 \ 5^x^-^2=5^1 \ x-2=1 \ x=1+2 \ x=3$