Question

2sin^{2} -0.5x-cos^{2} x=1[/tex]  prowu rewite mne sro4no nado kapec zavtra

Answer 1

$sin(-frac{x}{2})=-sinfrac{x}{2}\sin^2(-frac{x}{2})=(-sinfrac{x}{2})^2=+sin^2frac{x}{2}\2sin^2frac{x}{2}=1-cosx\1-cosx-cos^2x=1\cosx+cos^2x=0\cosx(1-cosx)=0\cosx=0,;; x=frac{pi}{2}+pi n,;; nin Z\1-cosx=0, cosx=1,;; x=2pi k, kin Z$