Question

4^X=20 решить уравнение

Answer 1

4^x=20
x=1/2 *log₂(20)
x=1/2*log₂(4*5)
x=1/2*(log₂(2²)+log₂(5))
x=1/2*(2+log₂(5))
x=1+1/2*log₂(5)
x≈2.16096