Question

5 sin 2x = 2 cosx
необходимо решить

Answer 1

$5 sin 2x = 2 cosx \ 10sinxcosx-2cosx=0 \ cosx(5sinx-1)=0 \ \ cosx=0 \ x= dfrac{ pi }{2}+ pi k;k in Z \ \ 5sinx-1=0 \ sinx= dfrac{1}{5} \ x=arcsin dfrac{1}{5}+ 2 pi k;k in Z \ x= pi - arcsindfrac{1}{5}+2 pi k; k in Z$