Question

помогите, срочно!!!!!!!!!!

Answer 1

1.
sin(2α) = 2*sinα*cosα = 2*sinα*sin(π/2 - α) - ЧТД
2.
sin⁴α - cos⁴α = - (sin²α + cos²α)*(cos² - sin²α) = -1*cos(2*α) - ЧТД.