Question

спаситииииииииии нуэно решить а график сама сделаю

Answer 1

x³ - 6x + 5 > 0                                            x² + x - 5 = 0                  
(x - 1)(x²+ x - 5) > 0                                   D = 1 - 4*5 = - 19 < 0 корней нет
                                                                 коэффициент при x² =1> 0, значит
                                                                 x² + x - 5 > 0 при любых х.Значит
                                    x - 1 > 0
                                    x > 1
                                    x ∈ (1 ; + ∞)