Question

Алгебра 8 класс, Срочно!!!!!!!!!!

Answer 1

u2 - 2u + 4/ 4u2 - 1 = (u-1)2 + 3/ (2u-1)*(2u+1)
2u2 + u/ u3 + 8 = u*(2u+1)/ (u+2)*((u-1)2 + 3
u + 2/ 2u2 - u = u+2/ u(2u -1)
1) (u-1)2 + 3/ (2u-1)*(2u+1) * u*(2u+1)/ (u+2)*((u-1)2 + 3 = u/ (2u-1)*(u+2)
2) u/ (2u-1)*(u+2) - u+2/ u(2u -1) = -4u-4/ u(2u-1)*(u+2)
u2+2u/5 = u*(u+2)/5
3) -4u-4/ u(2u-1)*(u+2) * u*(u+2)/5 = -4(u+1)/5(2u-1)
4) -4(u+1)/5(2u-1) - 10u+1/5(1-2u) = -4(u+1)/5(2u-1) + 10u+1/5(2u-1)= 3/5