Question

2x-8/2x-4≥3 как решить?

Answer 1

2х-4 ≠0 ⇒2х≠4 ⇒ х≠2

$frac{2x-8}{2x-4} geq 3 \ \ frac{2x-8}{2x-4} -3 geq 0 \ \ frac{2x-8-3*(2x-4)}{2x-4} geq 0 \ \ frac{2x-8-6x+12}{2x-4} geq 0 \ \ frac{-4x+4}{2x-4} geq 0 \ \ frac{4(1-x)}{2(x-2)} geq 0 \ \ frac{1-x}{x-2} geq 0 \ \ left { {{1-x leq 0} atop {x-2 textless 0}} right. \ \ left { {{x geq 1} atop {x textless 2}} right. \ \ 1 leq x textless 2 \ \ left { {{1-x geq 0} atop {x-2 textgreater 0}} right. \ \ left { {{x leq 1} atop {x textgreater 2}} right.$

решений нет

Ответ : 1 ≤ x < 2.