Question

log2(x-2)+log2(x+2)=log2(2x-1)

Answer 1

$log_2(x-2)+log_2(x+2)=log_2(2x-1)\ log_2((x-2)(x+2))=log_2(2x-1)\ (x-2)(x+2) = 2x-1\ x^2-4-2x+1=0\ x^2-2x-3\ x_1=-1, varnothing\ x_2=3$