Question

Помогите срочно пожалуста а) f (x)=3x^2-4x-4/3x^2-7x-6 x--->-2/3

Answer 1

$lim_{x to -{2over3}} {3x^2-4x-4over3x^2-7x-6}={{0over0}}\\3x^2-4x-4=0\D=16+3*16=4*16=(8)^2\x_1=2\x_2=-{2over3}\\3x^2-7x-6=0\D=121=(11)^2\x_1=3\x^2={-2over3}\\lim_{x to -{2over3}} {3x^2-4x-4over3x^2-7x-6}=lim_{x to -{2over3}} {3(x-2)(x+{2over3})over3(x-3)(x+{2over3})}={{-2over3}-2over{-2over3}-3}={8over11}$