Question

найдите производную подробно$f(x)=sqrt[3]{6 x^{2} +7}$

Answer 1

I hope this helps you



y=∛6x²+7


y'=(6x²+7)'/3.∛(6x²+7)³⁻¹


y' =(6.2.x+7.0)/3.∛(6x²+7)²


y'=4x/∛(6x²+7)²

Answer 2

f(x) = (6x²+7)^1/3

f '(x)=1/3 * (6x²+7)^1/3-1  * (6x²+7)' = 1/3 * (6x²+7)^-2/3 * 12x=4x * (6x²+7)^-2/3