Question

Найдите периметр треугольника ABC, если A(5;0), B(-3;6). С(0;2)

Answer 1

$P_{ABC}=|AB|+|BC|+|AC| \ \ |AB|= sqrt{(-3-5)^2+(6-0)^2}= sqrt{64+36}=10 \ |BC|= sqrt{(0-(-3))^2+(2-6)^2}= sqrt{9+16}=5 \ |AC|= sqrt{(5-0)^2+(0-2)^2}= sqrt{25+4}= sqrt{29} \ \ P_{ABC}=10+5+ sqrt{29}=15+ sqrt{29} approx20,4$

Ответ: 20,4