Question

найдите f'(2), если f(x) = $sqrt{-3x^2+6x+4}$

Answer 1

f'(x)=(1/2) * (1/(√(-3x²+6x+4)))  *  (-6x+6) = (-3x+3) / (√(-3x²+6x+4))
f'(2) = (-3*2+3) / (√(-3*2²+6*2+4))=(-3)/(√(4))=-3/2=-1.5