Question

4/х^2-9+х+1/х-3=1 решите пожалуйста

Answer 1

$frac{4}{ {x}^{2} - 9 } + frac{x + 1}{x - 3} = 1 \ frac{4}{(x - 3)(x + 3)} + frac{(x + 1)( x + 3)}{(x - 3)(x + 3)} = 1$
ОДЗ: х=/=±3
$frac{ {x}^{2} + 4x + 7 }{(x - 3)(x + 3)} = frac{ {x}^{2} - 9 }{(x + 3)(x - 3)} \ {x}^{2} - {x}^{2} + 4x + 16 = 0 \ 4x = - 16 \ x = - 4$