Question

lim(3x+6)/(x^3+8) x стремится к -2

Answer 1

lim= (3x+6)/(x^2+2^3)= 3(x+2)/(x+2)(x^2-2x+4)=3/(x^2-2x+4)=3/(4+4+4)=3/12=1/4

Answer 2

$lim_{n to -2} frac{3(x+2)}{(x+2)( x^{2} -2x+4)} = lim_{n to -2} frac{3}{( x^{2} -2x+4)} = frac{3}{ (-2)^{2} -2*(-2)+4}$=$frac{3}{4+4+4} = frac{3}{12} = frac{1}{4}$