Question

2|x-2 - 10|х+3= 50|x*2*+x-6 -1

Answer 1

2/(x-2)-10/(x+3)=50/(x^2+x-6)-1
x<>2 x<>-3
2(x+3)/(x-2)(x+3)-10(x-2)/(x+3)(x-2)=50/(x-2)(x+3)-(x2+x-6)/(x-2)(x+3)
2(x+3)-10(x-2)=50-(x^2+x-6)
2x+6-10x+20-50+x^2+x-6=0
x^2-7x-30=0
x12=(7+-корень(49+120)).2=(7+-13)/2= 10 -3
ответ -3 не подходит по ОДЗ x=10