Question

решите неравенство (x-4)/(x-3)≤0;

Answer 1

$frac{(x-4)} {(x-3)} leq 0$

$1) left { {{(x-4)} leq 0 atop {(x-3) textgreater 0}} right.$

$left { {{x} leq 4 atop {x textgreater 3}} right. Rightarrow 3 textless x leq 4$

2) $left { {{(x-4)} geq 0 atop {(x-3) textless 0}} right.$

$left { {{x} geq 4 atop {x textless 3}} right. Rightarrow$ нет решения

Ответ: $3 textless x leq 4$

Answer 2

спасибо