Question

Помогите пожалуйста решить:
lim = (sin^2* 5x)/4x^2
x->0

Answer 1

$limlimits _{x to 0} frac{sin^25x}{4x^2} =limlimits _{x to 0} Big ( underbrace {frac{sin5x}{5x}}_{1}cdot underbrace {frac{sin5x}{5x}}_{1}cdot frac{25}{4} Big )=1cdot 1cdot frac{25}{4}=6,25$