Question

(3к + 5) (к – 6) = 0

Answer 1

$(3k+5) (k-6) = 0$

$1) (3k+5) = 0 \\ 3k=-5 \\ k_1 = - \frac{5}{3}$

$2) (k-6) = 0 \\ k_2 = 6$

Ответ: $k_1 = - \frac{5}{3} \\ k_2 = 6$