Предмет: Алгебра, автор: 17768

Найти sin^a и cos^a если cosa = 3/7

Ответы

Автор ответа: Dm1itr1y

1) f' = -4*(2x+7)^-5 *2 -3*(1-x)^2*(-1) = -8/(2x+7)^5 +3*(1-x)^2
f'(-3) = -8/(-6+7)^5 +3*(1+3)^2 = -8+3*16 = -8+48 =40

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