Question

log₂2cos²π/12+log₂tgπ/12

Answer 1

$log_2 2cos^2 frac{pi}{12}+log_2 tg frac{pi}{12}=\\ log_2 (2cos^2 frac{pi}{12}tg frac{pi}{12})=log_2 (2cos frac{pi}{12}sin frac{pi}{12})=\\log_2 sin(2*frac{pi}{12})=log_2 sin frac{pi}{6}=\\log_2 frac{1}{2}=log_2 2^{-1}=-1$