Question

(x²+3x-2)²+3(x²+3x-2)-2=x

Answer 1

$(x^2+3x-2)^2+3(x^2+3x-2)-2=x\ x^4+3x^3-2x^2+3x^3+9x^2-6x-2x^2-6x+4+3x^2+9x-8=x\ x^4+6x^3+8x^2-4x-4=0\ (x^2+2x-2)(x^2+4x+2)=0\\ x^2+2x-2=0\ x^2+2x=2\ x^2+2x+1=3\ (x+1)^2=3\ x+1=sqrt3\ x_1 = sqrt3 - 1\ x+1=-sqrt3\ x_2=-sqrt3 - 1\\ x^2+4x+2=0\ x^2+4x+4=2\ (x+2)^2=2\ x_3=sqrt2 - 2\ x_4=-sqrt2 - 2$