Question

Срочно! Решить задания по алгебре

Answer 1

$80) cfrac{ sqrt{0.08}* sqrt{0.3} }{ sqrt{0.0015} }= sqrt{ cfrac{0.08*0.3}{0.0015} } = sqrt{ cfrac{0.08}{0.005} } = sqrt{16}=4 \\ \ \ 60) left( sqrt{16 cfrac{9}{10}}+ sqrt{19 cfrac{6}{10} right): cfrac{1}{ sqrt{250} } =left( sqrt{cfrac{169}{10}}} + sqrt{cfrac{196}{10} right)* cfrac{ sqrt{250} }{ 1} =\\\=left( {cfrac{13}{ sqrt{10} }}} + {cfrac{14}{ sqrt{10} } right)* sqrt{250} = cfrac{27* sqrt{25}* sqrt{10} }{ sqrt{10} }=27*5=135$


$91) sqrt{x^2-4x+4}+ sqrt{x^2-8x+16}= sqrt{(x-2)^2}+ sqrt{(x-4)^2}= \= x-2+x-4=2x-6$
при х = √7
$2x - 6=2 sqrt{7}-6$



$82) 14* sqrt[4]{27}* sqrt[12]{27}= 14* sqrt[4]{3^3}* sqrt[12]{3^3}=14*3^{ frac{3}{4} }*3^{ frac{3}{12} }=\=14*3^{ frac{3}{4} }*3^{ frac{1}{4} }=14*3=42$


$66) sqrt{2}* sqrt{15- sqrt{7} }* sqrt{15+ sqrt{7} } * sqrt{109}= \ = sqrt{2}* sqrt{(15- sqrt{7})( 15+ sqrt{7} )} * sqrt{109}=\=sqrt{2}* sqrt{225-7 } * sqrt{109}=sqrt{2}* sqrt{218} * sqrt{109}=\= sqrt{2}* sqrt{2}* sqrt{109}* sqrt{109}=2*109 =218$


$102) sqrt{21-12 sqrt{3} }* sqrt{21+12 sqrt{3} }= sqrt{(21-12 sqrt{3})(21+12 sqrt{3}) }=\= sqrt{441-144*3}= sqrt{441-432}= sqrt{9}=3$