Question

Хелпаните по алгебре,очень надо.Плачу 70 балов,срочно.

Answer 1

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Answer 2

Благодарю <3

Answer 3

2) (y+3)/(2y+2) - y+1/2y-2 + 3/y^2-1 = (y+3)/2(y+1) - (y+1)/2(y-1) + 3/(y+1)(y-1) = ((y+3)(y-1)-(y+1)(y+1)+6)/2(y+1)(y-1) = y^2

Answer 4

... =(y^2 -y+3y-3-y^2-y-y-1+6)/2(y+1)(y-1) = 2/2(y+1)(y-1) = 1/(y+1)(y-1)

Answer 5

3) (3b^2)/(b^3+1) - (b-1)/(b^2-b+1)= (b(3b-1)/(b+1)(b^2-b+1) - (b-1)/(b^2-b+1) =(3b^2-b-b^2-b+b+1)/(b^3+1) = 2b^2-b+1/b^3+1

Answer 6

№5 y=(x^2-16)/(x-4) - (2x^2-x)/x = ((x-4)(x+4))/(x-4) - x(2x-1)/x = x+4-2x+1 = -x+5 y=5-x, графиком является прямая