Question

решить!
log3(x+7)=log3(2x-1)

Answer 1

$log_3(x+7)=log_3(2x-1); ,; ;ODZ:; left { {{x+7 textgreater 0} atop {2x-1 textgreater 0}} right. ; left { {{x textgreater -7} atop {x textgreater frac{1}{2}}} right. ; to ; x textgreater frac{1}{2}\\x+7=2x-1\\7+1=2x-x\\8=x\\underline {x=8}$