Question

(8у-12)(2,1+0,3у)=0 помогите

Answer 1

16.8y+2.4y^2- 25.2-3.6y=0
2.4y^2+13.2y-25.2=0
Д=174.24+241.92=416.16

y1=(-13.2-20.4)/4.8=-33.6/4.8=-7
y2=(-13.2+20.4)/4.8=7.2*4.8=1.4