Question

дам 25........................

Answer 1

1. r_1, r1, Klass_10, _123
2.
y = sqr(a mod b) = sqr(4) = 16.
z = sqrt(trunc(a/b)) + y = sqrt(4) + 16 = 2 + 16 = 18
3. -5.1 * power(10, 5)
4. 71000000000
5. 
z := (sqrt(abs((x + y) / 2)))/(sqr(sqr(x+y) + 1.5));