Question

Вычислите предел на фото

Answer 1

$lim_{x to infty} frac{9x^3-4x^2}{10x^4+x} = lim_{x to infty} frac{x^4(frac{9}{x}-frac{4}{x^2})}{x^4(10+frac{1}{x^3})} = lim_{x to infty} frac{frac{9}{x}-frac{4}{x^2}}{10+frac{1}{x^3}} = frac{0-0}{10+0} = 0$