Question

Решите срочно пж!!! $frac{ (-2+i)^{2} }{1+3I}$

Answer 1

(-2+i)²/(1+3i)=(i-2)²/(1+3i)=(i²-4i+4)/(1+3i)=(-1-4i+4)/(1+3i)=(3-4i)/(1+3i)=
=(3-4i)(1-3i)/((1+3i)(1-3i))=(3-4i-9i+12i²)/(1²-(3i)²)=
=(3-13i-12)/(1+9)=(-9-13i)/10=-(0,9+1,3i).