Question

Помогите пожалуйста с уравнениями!Дам 59 баллов!
Нужно подробно разъяснить
1.)
5х+(3х-7)=9
б)3у-(5-у)=11
в)48=11-(9а+2)
г)13-(5х+11)=6х

2.)а)(7х+1)-(6х+3)=5
б)(8х+11)-13=9х-5
в)2=(3х-5)-(7-4х)
г)8х+5=119+(7-3х)

Answer 1

1a) 5x + (3x - 7) = 9     б) 3y - (5 - y) = 11    в) 48 = 11 - (9a + 2)         
5x + 3x - 7 = 9                  3y - 5 + y = 11         48 = 11 - 9a - 2
8x = 9 + 7                          4y = 11 + 5             9a = 9 - 48
8x = 16                              4y = 16                   9a = - 39
x = 2                                     y = 4                    a = - (4)1/3
г)13 - (5x + 11)= 6x
13 - 5x - 11 = 6x
- 5x - 6x = 11 - 13
- 11x = - 2
      x = 2/11
2a) (7x + 1) - (6x + 3) = 5
7x + 1 - 6x - 3 = 5
x = 5 - 1 + 3
x = 7
б)(8x + 11) - 13 = 9x - 5
8x + 11 - 13 = 9x - 5
8x - 9x = - 5 - 11 + 13
- x = - 3
x = 3
в) 2 = (3x - 5) - (7 - 4x)
2 = 3x - 5 - 7 + 4x
- 3x - 4x = - 5 - 7 - 2
- 7x = - 14
x = 2
г) 8x + 5 = 119 + (7 - 3x)
8x + 5 = 119 + 7 - 3x
8x + 3x = 119 + 7 - 5
11x = 121
x = 11

Answer 2

Спасибо большое!