Question

(4*sqrt(27)-sqrt(32)^3)-sqrt(108)^3+3*sqrt(48)

Answer 1

$=4sqrt{9}cdotsqrt{3}-32sqrt{32}-108sqrt{108}+3sqrt{16}cdotsqrt{3}$ = $12sqrt{3}-32sqrt{16}cdotsqrt{2}-108sqrt{36}cdotsqrt{3}+12sqrt{3}$ = $12sqrt{3}-128sqrt{2}-648sqrt{3}+12sqrt{3}$ = $-128sqrt{2} - 624 sqrt{3}$ = $-16(8sqrt{2}+39sqrt{3})$