Question

1) (2+6i)+(3-8i)
2)(2+6i)-(3-8i)
3)(2+6i)*(3-8i)
4)(2+6i)/(3+8i)

Answer 1

$1)quad(2+6i)+(3-8i)=5-2i\ 2)quad(2+6i)-(3-8i)=-1+14i\ 3)quad(2+6i)cdot(3-8i)=6+48-16i+18i=54+2i\ 4)quadfrac{2+6i}{3-8i}=frac{(2+6i)(3+8i)}{9-64}=frac{6-48+16i+18i}{-55}=frac{42}{55}-frac{34}{55}i$