Question

Сократите дробь:
В). m^2-n^2/mn+n^2
Д). z-1/a-az

Answer 1

В). m^2 - n^2/mn + n^2 = (m-n) (m+n)/n (m+n) = (m-n)/n

Д). z-1/a-az = z1/a(1-z)