Question

Решите уравнения (13х+29)в квадрате -19(13х+29)+48=0

Answer 1

(13x + 29)² - 19(13x + 29) + 48 = 0
Обозначим 13x + 29 = y, тогда
y² - 19y + 48 = 0
D = 19² - 4*48 = 169
Y1,2 = (19 + - 13) / 2
Y1 = (19 + 13) / 2 = 16
Y2 = (19 - 13) / 2= 3
13x + 29 = 16                            13x + 29 = 3
13x = - 13                                   13x = - 26
x = - 1                                          x = - 2