Question

ПОМОГИТЕ!!!!! номер 1.25

Answer 1

$2a^5-5a^4+a^3-3a^2\ a=-1 rightarrow 2cdot(-1)^5-5cdot(-1)^4+(-1)^3-3cdot(-1)^2=\ =-2-5-1-3=-11\ a=0 rightarrow 2cdot0^5-5cdot0^4+0^3-3cdot0^2=0\ a=2 rightarrow 2cdot2^5-5cdot2^4+2^3-3cdot2^2=\ =2^2(2^4-5cdot2^2+2-3)=4(16-20-1)=4cdot(-5)=-20$