Предмет: Алгебра, автор: Анастасия193

решите уравнение x^2-10x+25=a^2

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Автор ответа: paradiseva

$x^2-10x+25=a^2\ (x-5)^2=a^2\ (x-5)^2-a^2=0\ (x-5-a)(x-5+a)=0\ 1. x-5-a=0\ x=5+a\ 2. x-5+a=0\ x=a-5$

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