Question

Вычислите период функций
А)у=sin^2(x)
б)y=cos^2(x)
в)y=sin^2(x)-cos^2(x)

Answer 1

T=2π/|k|
k=2⇒T=2π/2=πА)у=sin^2(x)
y=1/2-1/2*cos2x
T=2π/|k|
k=2⇒T=2π/2=π

б)y=cos^2(x)
y=1/2+1/2*cos2x
T=2π/|k|
k=2⇒T=2π/2=π

в)y=sin^2(x)-cos^2(x)
y=-cos2x