Question

Решить уравнение:
(3x-1)(2x-2)=(x-4)^2+7

Answer 1

$(3x-1)(2x-2)=(x-4)^2+7\ 6x^2-6x-2x+2=x^2-8x+16+7\ 6x^2-8x+2-x^2+8x-23=0\ 5x^2-21=0\ 5x^2=21\ x^2= frac{21}{5}\ x= +-sqrt{ frac{21}{5}} \ x=+- frac{ sqrt{105} }{5}$