Question

(2а-3в)^2-(2а+3в)^2
______________
5 ав

Answer 1

$frac{(2a-3b)^2-(2a+3b)^2}{5ab}$
$(a-b)^{2} =a^{2} -2ab+ b^{2}$
$(a+b)^{2} =a^2+2ab+b^2$
$frac{4a^2-12ab+9b^2-4a^2-12ab-9b^2}{5ab} = frac{-24ab}{5ab} = frac{-24}{5} =-4,8$