Question

Найдите корни уравнений
1.(3x-1)^2=(3x-4)^2
2.x^2+7=(7+x)^2

Answer 1

1.(3x-1)^2=(3x-4)^2
(3x-1)²-(3x-4)²=0
(3x-1-3x+4)(3x-1+3x-4)=0
3(6x-5)=0
6x-5=0
6x=5
x=5/6
2.x^2+7=(7+x)^2
x²+2=49+14x+x²
x²+14x-x²=2-49
14x=-45
x=-45/14
x=-3 3/14

Answer 2

1.(3x-1)^2=(3x-4)^2
(3x-1)²-(3x-4)²=0
(3x-1-3x+4)(3x-1+3x-4)=0
3(6x-5)=0
6x-5=0
6x=5
x=5/6
2.x^2+7=(7+x)^2
x²+2=49+14x+x²
x²+14x-x²=2-49
14x=-45
x=-45/14
x=-3 3/14