Question

Решите пример:
(97^3+83^3)÷180-97*83))÷(35^2-28^2)

Answer 1

$mathtt{(frac{97^3+83^3}{180}-97*83):(35^2-28^2)=frac{frac{(97+83)(97^2-97*83+83^2)}{180}-97*83}{35^2-28^2}=}\mathtt{frac{97^2-97*83+83^2-97*83}{(35-28)(35+28)}=frac{(97-83)^2}{7*63}=frac{14^2}{49*9}=frac{7^2*2^2}{49*9}=frac{4}{9}}$