Question

Помогите решить плиз
(2х-1)^2-(х-1)(х+7)≤5

Answer 1

(2x-1)² - (x-1)(x+7) ≤ 5
(2x-1)² ≤ 5
(2x-1)(2x-1) ≤ 5
4x² - 4x + 1 ≤ 5
4x² - 4x - 4 ≤ 0
x² - x - 1 ≤ 0
x(x-1) ≤ 1
x ≤ 1
x - 1 ≤ 1
x ≤ 2
[1;2]

- (x-1)(x+7) ≤ 5
(x-1)(x+7) _> 5
x-1 _> 5
x _> 6
x+7 _> 5
x _> -2
[-2;5]