Question

Помогите, пожалуйста!!!!!!!! Математика

Answer 1

$frac{1+sqrt{3}}{2}sin 2x=(sqrt{3}-1)cos^2 x+1;\ frac{1}{2}+frac{sqrt{3}}{2}sin 2x=sqrt{3}cos^2 x-cos^2 x+sin^2x+cos^2x;\ frac{1}{2}cos^2 x +frac{1}{2}sin^2 x+sqrt{3}sin xcos x=sqrt{3}cos^2 x+sin^2x;\ (sqrt{3}-frac{1}{2})cos^2 x+frac{1}{2}sin^2 x+sqrt{3}sin xcos x=0;,|:cos^2 x\ sqrt{3}-frac{1}{2}+frac{1}{2}{rm tg}^2 x+sqrt{3},{rm tg},x=0,,t={rm tg},x;\ frac{1}{2}t^2+sqrt{3}t+frac{2sqrt{3}-1}{2}=0;\ t^2+2sqrt{3}t+2sqrt{3}-1=0;$
$D'=3-2sqrt{3}+1=4-2sqrt{3}=(sqrt{3}-1)^2;\ t_{1,2}=sqrt{3}pmsqrt{3}mp1Rightarrow t_1=2sqrt{3}-1,,t_2=1.\ x_1={rm arctg},(2sqrt{3}-1)+pi k,, kin Z\ x_2=frac{pi}{4}+pi k,, kin Z.$