Question

решите уравнение (x+4)^2+x^2=2x-1

Answer 1

$(x+4)^2+x^2=2x-1 \ 2x^2+8x+16=2x-1 \ 2x^2+8x+16-left(2x-1right)=2x-1-left(2x-1right) \ 2x^2+6x+17=0 \ D=frac{-6+sqrt{6^2-4cdot :2cdot :17}}{2cdot :2}= sqrt{36-136} = sqrt{-100} \ boxed{NET KORNEY ,tk - D textless 0}$