Question

Представьте в виде многочлена
1) (4m-n)(4m+n)-(4m-n-4)^2
2)(x+1)^3-(x-4)(x^2+4x+16)

Answer 1

1) (4m-n)(4m+n)-(4m-n-4)^2=16m²-n²-16m²+8mn-n²+32m-8n-16=
=-2n²+8mn+32m-8n-16
2)(x+1)^3-(x-4)(x^2+4x+16)=x³+3x²+3x+1-x³+64=3x²+3x+65

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