Question

Помогите пожалуйста решить неравенство

Answer 1

|sin2x|≤√3/2
-√3/2≤sin2x≤√3/2
-π/3+2πk≤2x≤π/3+2πk U 2π/3+2πk≤2x≤4π/3+2πk
-π/6+πk≤x≤π/6+πk U π/3+πk≤x≤2π/3+πk
x∈[-π/6+πk;π/6+πk] U [π/3+πk;2π/3+πk],k∈z