Question

9x^4-6x^2+1+x^2-4=1 помогите решить

Answer 1

$diaplaystylemathtt{(3x^2-1)^2+(x-2)(x+2)=1;~9x^4-6x^2+1+x^2-4=1;}\diaplaystylemathtt{9x^4-5x^2-4=0;~[x^2=y,y textgreater 0]~9y^2-5y-4=0;}\diaplaystylemathtt{D=b^2-4ac=(-5)^2-4*9*(-4)=25+144=169=13^2~to~}\diaplaystylemathtt{y_{1,2}=frac{5б13}{18}~toleft[begin{array}{ccc}mathtt{y_1=frac{5+13}{18}=1}\mathtt{y_2=frac{5-13}{18}=-frac{4}{9}notin ODZ}end{array}rightto~x^2=1to~x=б1}$