Question

log 6 (3x+2) больше или равно 1

Answer 1

$log_6(3x+2) geq 1; ,; ; ; ODZ:; 3x+2 textgreater 0; ,; x textgreater - frac{2}{3}\\log_6(3x+2) geq log_66\\3x+2 geq 6\\3x geq 4\\x geq frac{4}{3}\\xin [, 1frac{1}{3},+infty )$

Answer 2

{3x+2>0⇒3x>-2⇒x>-2/3
{3x+2≥6⇒3x≥6-2⇒3x≥4⇒x≥4/3
x∈[4/3;∞)