Предмет: Алгебра,
автор: doda4
Ребята, помогите, математика
Приложения:
![](https://files.topotvet.com/i/804/804d833079e4f411980fd2d5d8dd7698.png)
Ответы
Автор ответа:
0
(x²-3|x|-3)/(|x|+2)≤1
1)x<0
(x²+3x-3)/(-x+2)≤1
(x²+3x-3)/(-x+2) -1≤0
(x²+3x-3+x-2)/(2-x)≤0
(x²+4x-5)/(2-x)≤0
x²+4x-5=0
x1+x2=-4 U x1*x2=-5⇒x1=-5 U x2=1
2-x=0⇒x=2
\\\\\\\\\\\ \\\\\\\\\\\\
+ _ + _
----------------[-5]---------(0)------[1]--------------(2)--------------------
\\\\\\\\\\\\\\\\\\\
x∈[-5;0)
2)x≥0
(x²-3x-3)/(x+2)≤1
(x²-3x-3)/(x+2) -1≤0
(x²-3x-3-x-2)/(x+2)≤1
(x²-4x-5)/(x+2)≤0
x²-4x-5=0
x1+x2=4 U x1*x2=-5⇒x1=-1 U x2=5
x+2=0⇒x=-2
\\\\\\\\\\\ \\\\\\\\\\\\\\
_ + _ +
------------------(-2)--------------[-1]----------[0]----[5]----------------
\\\\\\\\\\\\\\\\\\\
x∈[0;5]
Общий x∈[-5;5]
наим -5,наиб 5,произведение -5*5=-25
Ответ -25
1)x<0
(x²+3x-3)/(-x+2)≤1
(x²+3x-3)/(-x+2) -1≤0
(x²+3x-3+x-2)/(2-x)≤0
(x²+4x-5)/(2-x)≤0
x²+4x-5=0
x1+x2=-4 U x1*x2=-5⇒x1=-5 U x2=1
2-x=0⇒x=2
\\\\\\\\\\\ \\\\\\\\\\\\
+ _ + _
----------------[-5]---------(0)------[1]--------------(2)--------------------
\\\\\\\\\\\\\\\\\\\
x∈[-5;0)
2)x≥0
(x²-3x-3)/(x+2)≤1
(x²-3x-3)/(x+2) -1≤0
(x²-3x-3-x-2)/(x+2)≤1
(x²-4x-5)/(x+2)≤0
x²-4x-5=0
x1+x2=4 U x1*x2=-5⇒x1=-1 U x2=5
x+2=0⇒x=-2
\\\\\\\\\\\ \\\\\\\\\\\\\\
_ + _ +
------------------(-2)--------------[-1]----------[0]----[5]----------------
\\\\\\\\\\\\\\\\\\\
x∈[0;5]
Общий x∈[-5;5]
наим -5,наиб 5,произведение -5*5=-25
Ответ -25
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